Superliga (Brazilian volleyball) · Saturday, 21 November, (UTC+3)
Volei Renata — Monte Carmelobeta
☆ Save matchModel prediction for 21 November
Preliminary forecast: the match is more than a week away. Closer to it the model takes in fresh form, injuries and line-ups, and the numbers may move.
In short
Volei Renata are clear favourites: 86% against 14% for the opponent.
The most likely score in sets is 3:0. The model expects about 176 points in the match. First set: Volei Renata — 73%.
Over 176.5 points — 49%.
Why
- Elo rating by sets: Volei Renata 1683, Monte Carmelo 1505; chance to win a single set: Volei Renata 73%.
Facts
- Last 5 meetings: Volei Renata 4 wins, Monte Carmelo 1.
Probabilities
| First set: Volei Renata | 73% |
| First set: Monte Carmelo | 27% |
| Points over 176.5 | 49% |
| Points under 176.5 | 51% |
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The chance of every score in sets, set handicaps and totals, every points total, the teams’ ratings and how the estimate moved before the match.
- Score in sets
- Sets handicap Volei Renata
- Total sets
- All points totals
- Teams’ Elo ratings by sets
Form
- 04.11away · Sao Jose dos Campos3:2
- 27.10away · Norde Volei3:0
- 10.05away · Sada Cruzeiro0:3
- 28.04away · Praia Clube3:0
- 23.04Praia Clube3:1
- 04.11Suzano Volei3:1
- 30.10away · Sada Cruzeiro0:3
- 25.10away · Guarulhos1:3
- 10.04Volei Renata1:3
- 05.04away · Volei Renata1:3
Head to head
- 10.04.2026Monte Carmelo — Volei Renata1:3
- 05.04.2026Volei Renata — Monte Carmelo3:1
- 10.01.2026Monte Carmelo — Volei Renata3:2
- 24.10.2025Volei Renata — Monte Carmelo3:0
- 30.01.2024Volei Renata — Monte Carmelo3:2
Superliga on the same day
- GoiasMontes Clarospreliminary50501The model's most likely outcome: 1Model's score: 3:1188.5
- Praia ClubeGuarulhospreliminary62381The model's most likely outcome: 1Model's score: 3:1187.5
- Sao Jose dos CamposSada Cruzeiropreliminary6942The model's most likely outcome: 2Model's score: 0:3147.5
This is the model’s statistical estimate, not a recommendation. An outcome at 86% will not happen in roughly 14 matches out of 100. How to read probabilities →